Question

30.
In Figure-8, ABCD is a parallelogram. A semicircle with centre O and the
diameter AB has been drawn and it passes through D. 11
AB = 12 cm and OD I AB, then find the area of the shaded region,
(Use n = 3.14)

Answer 1

Area of Parallelogram= 12×6=72 cm square.

Area of Quadrant = 1/4×314/100×6×6=28.26 cm square. Area of shaded region = Area of parallelogram - Area of Quadrant Area = 72-28.26Area=43.74 cm square.

Answer 2

The area of the shaded region is 43.74 cm^2

Given,

ABCD is a parallelogram.

A semicircle with centre O and the  diameter AB passing through D.

AB = 12 cm and OD I AB

OA = OB = OD = AB/2 - 12/2 = 6 cm

Area of shaded region = Area of parallelogram ABCD - Area of quadrant DOB

= base × height - πr^2/4

= AB × OD - π/4 × (OB)^2

= 12 × 6 - 3.14/4 × 6^2

= 72 - 0.785 × 36

= 43.74 cm^2.

Hence the area of shaded portion.