30.
In Figure-8, ABCD is a parallelogram. A semicircle with centre O and the
diameter AB has been drawn and it passes through D. If
AB = 12 cm and OD I AB, then find the area of the shaded region.
(Use = 3.14)
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Answer:
AB = 12cm
AO=OB=OD=12cm
Base = AB = 12cm
Height = OD = 6cm
Area of parallelogram = Base × Height
= 12 × 6
= 72 cm2
Radius = 6cm
Area of quadrant DOB = 1/4 × πr2
= 1/4 × 3.14 × 6 × 6
= 1/4 × 3.14 × 36
= 1/4 × 113.04
= 28.26 cm2
Area of shaded region
= Area of parallelogram - Area of quadrant
= 72 - 28.26
= 43.74 cm2
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