Question

30 litre of ammonia gas at 30°C and 40 atm pressure is allowed to expand in a
40 litre capacity and pressure becomes 20 atm. Calculate the drop in temperature

Hint :- P1V1/T1 = P2V2/T2 , where T2= 202K . drop in temperature = T1- T2​

Answer 1

Answer:

101K

Explanation:

V₁ = 30 L

T₁ = 30+273

303 k

P₁ = 40 atm

V2 = 40L

P2 = 20 atm

To find : T₁-T₂²

Applying Combined Law

=> 40 x 30 = 20 x 40

303

12

T₂ = 202K.

T₁-T₂= 303-202

T₁

1200 = 800

303 T2

1200T₂ = 242400

T2₂ = 242400

12.00