Question

30 ml of 0.1,normality bacl3 is mixed with 40 ml of 0.2 normality al2 （so4）3 how many grams of baso4 formed​

Answer 1

Answer:

3BaCl

2

+Al

2

(SO

4

)

3

→3BaSO

4

+2AlCl

3

Mole before reaction 30×0.2 40×0.3 0 0

=6 =12

Mole after reaction 0 6 6 6

6 Meq. of BaCl

2

reacts with 6 Meq. of Al

2

(SO

4

)

3

to produce 6 Meq. of BaSO

4

and 6 Meq. of AlCl

3

.

∴ Meq. of BaSO

4

formed =6=

E

Wt.

×1000; [E=

2

233

]

wt. of BaSO

4

formed =

1000

6×E

=

2×1000

6×233

=0.70g