Chemistry, asked by prahlad1234july, 2 months ago

30 ml of 0.12 N acid solution is neutralised by 20 ml of NaoH . Calculate the strength of NaoH in gram/liter​

Answers

Answered by usernametaken8
5

Explanation:

Let the strength of NaOH be x

Equating equivalents,

30×0.12 = x×20

=> x = 3/2 × 0.12 = 0.18 N

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