30% passengers from a train got down at station A;70% of the remaining got down at station B. If there are still 1050 passengers in the train. How many passengers were there before station A. provided no one boarded the train at station A and B.
Answers
Given :-
- 30% passengers from a train got down at station A
- 70% of the remaining got down at station B.
- If there are still 1050 passengers in the train.
To Find :-
- How many passengers were there before station A.?
Solution :-
Let us assume that, there were x passengers before station A .
Then,
→ 30% passenger got down at station A = 30% of x = (30 * x)/100 = 0.3x passenger .
So,
→ Passenger left in train = x - 0.3x = 0.7x
now,
→ 70% of remaining got down at station B = 70% of 0.7x = (70 * 0.7x)/100 = 0.49x
So,
→ Passenger left in train = 0.7x - 0.49x = 0.21x
given that, there are still 1050 passengers in the train.
therefore,
→ 0.21x = 1050
→ 21x = 1050 * 100
dividing both sides by 21,
→ x = 5000 (Ans.)
Hence, there were 5000 passengers before station A .
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