Question

30 points-- divide- -39x^4 by sq. root of 13x^4​

Answer 1

Step-by-step explanation:

$\frac{39 {x}^{4} }{ \sqrt{13 {x}^{4} } }$

$= \frac{39 {x}^{4} }{ {x}^{2} \sqrt{13} }$

$= \frac{13 \times 3 {x}^{4 - 2} }{ \sqrt{13} }$

$= \frac{ \sqrt{13} \times \sqrt{13} \times 3 {x}^{2} }{ \sqrt{13} }$

$= 3 \sqrt{13} {x}^{2}$