Question

30 points.In the figure, AD= AE, BD=CE. prove that triangle AEB = triangle ADC. Please give good statements.

Answer 1

given AD=AE,BD=CE.
proof: AEB= ADC
AD=AE(given)
Angle A=Angle A(common side)
BD=CE(given)
therefore, AEB= ADC(SAS congruency)

Answer 2

we have AD=AE (given)
and on adding second equation given in question, we get AD+BD=AE+CE.
AB =AC.
now Angle A is common in both triangle.
so by SAS congruence criteria.
triangle AEB,=triangle ADC.
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