Question

30 POINTS!!! PLS HELP
The product of two consecutive natural numbers is greater than their sum by 155. Find these numbers.

Answer 1

so, let numbers be

xx and x+1

now according to the equation

(x)(x + 1) = (x)+(x + 1) +155

$x^{2} + x = 2x + 156$

$x^{2} - x - 156 = 0$

$x^{2} - 13x + 12x - 156 = 0$

$x(x - 13) + 12(x - 13)$

$(x + 12)(x - 13)$

so, the numbers are

-12, -11 or 13, 14

Hope you get, your answer

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Answer 2

The consecutive numbers are 13 and 14.

Step-by-step explanation:

Let the consecutive numbers be x and x+1

According to question, we get that

$x(x+1)-(x+x+1)=155\\\\x^2+x-2x-1=155\\\\x^2-x=155+1\\\\x^2-x-156=0\\\\x^2-13x+12x-156=0\\\\x(x-13)+12(x-13)=0\\\\(x-13)(x+12)=0\\\\x=13,-12$

So, the consecutive numbers are 13 and 14.