Question

30 Points

Provide Steps with answer

Answer 1

displacement vector ( AB) = position vector of B - position vector of A
= ( 5 i -3j -1k) - ( 2i +2 j +4 K)
= (5 -2)i + (-3 -2)j + (-1 -4) K
=3i -5 j -5k

unit vector of force acting along AP
so,
F/|F| = AP/|AP|

AP = ( 10-2)i +(2-2)j +(-11-4)K = 8i -15k
so,
F= |F|(AP/|AP| )
=34(8i -15k)/17
=16i -30k

(2) work done = dot product of F and displacement
W = F.S
W = AP.AB

= (16i -30k ).(3i -5j -5k)
= 48 +0 + 150
= 198 Joule