Question

30 points question
Plz ans it fast and explain according to 10th class

Q.Does (-a^2 - b^2 - 2ab) = (a+b)^2

Answer 1

Answer:

No.

Step-by-step explanation:

$(-a^2 - b^2 - 2ab) \neq (a+b)^2\\\\\because (-a^2 - b^2 - 2ab) = -(a^2+b^2+2ab) = -(a+b)^2 \neq (a+b)^2$

Hope it helps!

Answer 2

Answer:

Since (A) is the intermediate reactive species whose concentration is determined from equilibrium step.

Slow step is:

A + B

2

→AB+B (slow)

r = k[A][B

2

]

From equilibrium step

A

2

⇌A+A(fast)

k

eq

=

[A

2

]

[A]

2

∴[A]=(k

eq

[A

2

]

1/2

Substitute the value of [A] in equation (i),

r=k.k

eq

1/2

[A

2

]

1/2

[B

2

]

Thus, order of reaction =

2

1

+1=1

2

1