Question

30 points question
$\sin(thita)=\frac{4}{5} \\ then \: \tan(thita) =$
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Answer 1

let theta be x

thus

sin x = 4/5

sin²x+cos²x=1

16/25 + cos²x = 1

cos²x= 1-16/25

cos²x=9/25

cosx=3/5

thus

tanx = sinx/cosx

thus

tanx=4/3