◆◆30 points question ◆◆The population of a town increases at a rate of 40 per thousand. Its population after 2 years will be 6084. find its present population..
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33
Soln:-
Rate =40/1000=4/100=4℅
Population after 2years =6084
let the present population be x
A=P(1+r/100)^t
6084=x(1+4/100)^2
6084=x(1+1/25)^2
6084=x(26/25)^2
6084=x(26/25×26/25)
6084=x×(676/625)
x=6084×625/676
=5625
so the present population of the town is 5625
Rate =40/1000=4/100=4℅
Population after 2years =6084
let the present population be x
A=P(1+r/100)^t
6084=x(1+4/100)^2
6084=x(1+1/25)^2
6084=x(26/25)^2
6084=x(26/25×26/25)
6084=x×(676/625)
x=6084×625/676
=5625
so the present population of the town is 5625
aliya7696:
how did u get that formula "A=P(".....
i know
Answered by
11
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