Question

30. Prove that Sin 63 Cos 27°+Cos 63º Sin 27°=1​

Answer 1

Answer:

sin(63+27)=1

sin90=1

1=1

Answer 2

Answer:

$\sin(63) \times \sin(63) + \cos(63) + \cos(63)$

${ \sin(63) }^{2} + { \cos(63) }^{2}$

===1