30.Rohan had (−4x − 12y + 6z) rupees. He spent 7x − 3y + 8z to buy new
clothes.How much is left with him now?
Answers
Answered by
3
Answer:
Rohan had - (-4x-12y+6z) rupees
he spent- (7x-3y+8z) rupees
money left= (-4x -12y +6z) - (7x -3y +8z )
= -4x -12y +6z -7x +3y -8z
= ( -11x -9y -2z )
or = -(11x +9y+2z)
Answered by
4
Answer:
Money left with Rohan = Rs.(-11x - 9y - 2z)
Step-by-step explanation:
We know that,
Total money he has = Rs.(-4x - 12y + 6z)
Total money he spent = Rs.(7x - 3y + 8z)
We know that,
Total money left = Total money he has – Total money he spent
Thus,
Money left = (-4x - 12y + 6z) - (7x - 3y + 8z)
Opening the brackets
= -4x - 12y + 6z - 7x + 3y - 8z
= -4x - 7x - 12y + 3y + 6z - 8z
= (-11x - 9y - 2z)
Thus,
Money left with Rohan = Rs.(-11x - 9y - 2z)
Hope it helped and you understood it........All the best
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