30 spherical balls of radius 7 cm each are dropped in a cylindrical tank of radius 49 cm. If the tank is already filled up to a height of
20/7 m, then find the percentage increase in height.
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Answer:
200%
Step-by-step explanation:
Given:
No. of spherical balls = 30
Radius of balls = 7 cm
Radius of cylinder = 49 cm
Filled height of cylinder = 20/7 cm
Find: Percentage increase in height
Solution-
Let increase in height of cylinder is h.
Thus, increased volume of cylinder = pi x r x r x h
= pi x 49 x 49 x h cubic cm (1)
Volume of 30 spherical balls = 30 x 4/3 x pi x 7 x 7 x 7 cubic cm (2)
Equating equations 1 and 2, we get
h = 40 / 7
So percentage increase in height = (40/7) x 100 / (20/7) = 200%
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