30 The base of a right angled triangle is 5m and its hypotenuse is 13 m. find its area?
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AC^2=AB^2+BC^2
AC^2=5^2+13^2
AC^2=25+169=194
AC^2=5^2+13^2
AC^2=25+169=194
Answered by
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Base=5m
H=13m
Then;altitude=root of (hypotenuse square -base square)=13*13-5*5=169-25=144=12m
Area =1/2base*height=1/2*5*12=30m.sq
H=13m
Then;altitude=root of (hypotenuse square -base square)=13*13-5*5=169-25=144=12m
Area =1/2base*height=1/2*5*12=30m.sq
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