Question

30. The force versus position (F - x) graph of a particle
of mass 2 kg is shown in the figure. If at x = 0
velocity of particle is 2 m/s then velocity of the
particle at x = 8 m will be
1.2√11
2.√22
3.2√22
4.4√11
someone tell fast ​

Answer 1

Answer:

The figure shows the force (F) versus displacement (s) graph for a particle of mass m=2kg initially at rest

Answer 2

Answer:

opeion 1 : 2$\sqrt{11}$

Explanation:

we know that : adx = vdv

$\frac{1}{m}$  $\int\limits^8_0 {F} \, dx$ = $\int\limits^v_2 {v} \, dv$

$\frac{1}{2}$ ( ($\frac{1}{2}$ * 10 *10 ) - ( 5 * 2 )) = $\frac{v^{2}-2^{2} }{2}$

40 = $v^{2}$ - 4

$v^{2}$ = 44

v = $\sqrt{44}$

v = 2 $\sqrt{11}$