Question

30.) The length of rectangle exceeds its breadth by 4 cm. If length and breadth are each increased by 3 cm
the area of the new rectangle will be 81square cm more than that of the given rectangle. Find the dimentions of the
rectangle.​

Answer 1

❣️❣️Hey mate ❣️❣️

Here is the solution :-

Let the breadth be X .

then, lenght = x + 4 cm

Area = {x ( x + 4) } cm²

=> x² + 4x

Given ,

Length & breadth are increased by 3 cm :-

Then,

length = {(X + 4) + 3} cm = x + 7 cm

breadth = (X + 3 ) cm

Area = ({ x+ 7) (x +3) } cm²

=> (x² + 3x + 7x + 21 )

=> (x² + 10x + 21 ) cm²

Given,

The lenght of the new rectangle is 81cm² more than the original rectangle :-

Then, according to the question :-

=> (x²+ 10 x + 21 ) - (x² + 4x) = 81

=> x² + 10x + 21 - x² - 4x = 81

=> 6x + 21 = 81

=> 6x = 81 - 21

=> 6x = 60

=> x = 10

The breadth is 10 cm and the lenght is (X+4) = 14 cm (of original rectangle)

The dimensions is :-

10 cm × 14 cm

Hope it will help you....

mark it as a brainleist...❣️❣️❣️