30. The length of the common chord of two intersecting circles is 24 cm. If the diameters of the circles are 30 cm and 26 cm, find the distance between their centres.
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Centre A circle radius is =250=25 cm
Centre B radius is =234=17 cm
Segment DS is the chord
DS=30 cm (given)
As DM=2DS=15 cm
In △AMD, By using Pythagoras theorem
AD2=AM2+MD2
AM2=AD2−MD2
AM2=(25)2−(15)2
AM2=400
AM=20 cm
Now in △BMD using Pythagoras
BD2=DM2+MB2
MB2=BD2−DM2⇒ 172−152
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