Question

30. The magnetic needle of tangent galvanometer is
deflected at an angle 30º due to a magnet. The
horizontal component of earth's magnetic field is
0.34 x 10-4 T along the plane of the coil. Then the
magnetic intensity will be
(1) 1.96 * 105 T (2) 1.96 104 T
(3) 1.96 * 10-4T (4) 1.96 * 10-5 T​

Answer 1

Answer:

Magnetic intensity is B = $(1.96)\times 10^{-5} T$

Explanation:

In this question

We have been given that

Value of the magnetic field is  0.34\times  10^{-4} T

Deflected at an angle 30°

So, we can find the value of magnetic intensity

vector quantity pertaining to the condition at any point under the magnetic influence like an electric current, or an electromagnetic wave measured by the force exerted on a vacuum upon a free unit north pole placed at the point.

magnetic intensity B = $B_H\times tan\theta$

                                 B = ${0.34\times  10^{-4}}\times tan30$

                                 B =  $1.96\times 10^{-5} T$

Hence, Magnetic intensity is $1.96\times 10^{-5} T$