Question

30. The value of a machine depreciates at the rate of 10% per annum It was purchased 3 years
ago. If its present value is 291600, for how much was it purchased?​

Answer 1

Answer:

Rs 4,00,000

Step-by-step explanation:

Let the price, before 3 year, of machine be 'a'.

After 1 year:

= > price = original price - 10% of original price

= > price = a - 10% of a = a - (10/100)a

= > price = a - (1/10)a = (10a-1a)/10

= > price = 0.9a

After 2 year:

= > price = 0.9a - 10% of 0.9a = 0.9a - (10/100)(0.9a)

= > price = 0.9a - (0.9/10)a = (9a-0.9a)/10

= > price = 0.81a

After 3 year:

= > price = 0.81a - 10% of 0.81a = 0.81a - (10/100)(0.81a)

= > price = 0.81a - (0.81/10)a = (8.1a-0.81a)/10

= > price = 0.729a

In question,

= > price after three year = Rs 291600

= > 0.729a = Rs 291600

= > a = Rs (291600/0.729)

= > a = Rs 4,00,000

Original price of machine was Rs 4,00,000

Answer 2

$\color{blue} {} AnSwER$

.

.

.

:depreciate rate=10%

Time= 3 years

Present value=291600

A= P =[1+r/100>]power n

291600= P[1+10/100] power 3

P=₹377321

$\color{red} {} p=377321$

$\color{orange} {} price .of machine.$