Question

30. The value of the height in the adjoining figure is, at which the tennis ball mist be hit, so that it will just pas over the net and land on away from the base of the net.​

Answer 1

Given :- In Given Fig The length AD = 18 m

AB= 6m, BD = 12m, BC = 0.9m

Now As we Know

$\frac{A B}{A D}=\frac{B C}{D E}\\\frac{6}{18}=\frac{0.9}{h}$

$h=\frac{18 \times 0.9}{6}\\h=27 \mathrm{~m}$

Answer 2

Answer:

h= 2.7m

Step-by-step explanation:

AB/AD = BC/DE

putting the value in the formula but remember AD=AB+BD

6/18=0.9/DE

Cross-Multiplying it,

6DE=18 x 0.9

DE= 18 x 0.9 / 6

DE = 2.7 m

Therefore h = 2.7 m

It is the Answer.

Hope This helps !!!