30. The velocity vector of a particle moving over a horizontal plane is given by y = 2ti +3t^2j. The ratio of the magnitude of
instantaneous acceleration of the particle at t = 2 sec to the magnitude of displacement of the particle during the interval
of first 2 sec is
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Answer:
(√37)/2(√5) { (Root 37) by (two root 5) }
Explanation:
I hope u know some basics of differentiation and integration and relations between acceleration, velocity and displacement...
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