Question

30. The velocity vector of a particle moving over a horizontal plane is given by y = 2ti +3t^2j. The ratio of the magnitude of
instantaneous acceleration of the particle at t = 2 sec to the magnitude of displacement of the particle during the interval
of first 2 sec is

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Answer 1

Answer:

(√37)/2(√5) { (Root 37) by (two root 5) }

Explanation:

I hope u know some basics of differentiation and integration and relations between acceleration, velocity and displacement...

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