Question

30. The zeroes of the polynomial
P(x) = x4-16 a
...
A) + 2
B) 4
C) † 2, 1-4
D) +2, +4​

Answer 1

For zeros of any polynomial f(x) , put it equal to zero(0).

P(x) = x^4 - 16

For zeros of P(x) :

P(x) = 0

x^4 - 16 = 0

(x^2 + 4)(x^2 - 4) = 0

(x^2 + 4)(x + 2)(x + 2) = 0

Now , (x^2 + 4) can never be zero for all real values of x.

Thus , (x + 2)(x - 2) = 0

=> x = +2 or -2

=> x = ±2

Hence, the answer is (A) +2.