Question

30. Using quadratic formula, solve the following quadratic equation for: p^2x^2+(p^2-q^2)x-q^2=0.​

Answer 1

Answer:

$x = \frac{ {q}^{2} }{ {p}^{2} } \\ x = - 1$

Step-by-step explanation:

p²x²+(p²-q²)x-q² = 0

$Quadratic \: formula = \frac{ - b± \sqrt{b²-4ac} }{2a} \\ = \frac{ -(p²-q²)± \sqrt{(p²-q²)² + 4p²q²} }{2p²} \\ = \frac{ -p² + q²± \sqrt{p⁴+q⁴-2p²q² + 4p²q²} }{2p²} \\ = \frac{ -p² + q²± (p²+q²) }{2p²} \\ x = \frac{ {q}^{2} }{ {p}^{2} } , x= - 1$

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