Question

30. We have four resistors A,B,C and D of resistance 4ohm, 8ohm 12 ohm and 24 ohm
respectively?:) Lowest resistance which can be obtained by combining these four resistors. ii) highest
resistance which can be obtained by combining these four resistors​

Answer 1

lowest resistance is 2 which we find by connected these resistors in parallel

parallel formula is

1/R=1/R+2/R+3/R

BY THIS YOU CAN FIND YOUR LOWEST RESISTANCE

highest resistance is 48 you can find this resistance by connecting all these resistors in series

series formula is

R=R1+R2+R3

BY THIS YOU CAN FIND YOUR ANSWER WHICH IS 48 IN SERIES THIS IS HIGHEST RESISTANCE

lowest is two and highest is 48

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Answer 2

Given:

Four resistors A, B, C, and D having the resistance

= 4 ohm, 8 ohm, 12 ohm and 24 ohm

To Find:

i) Lowest resistance which can be obtained by combining these four resistors.

ii) Highest  resistance which can be obtained by combining these four resistors​

Calculating:

i)

The formula to calculate the resistance in parallel circuit:

1/Rn = 1/R1 + 1/R2 + 1/R3 + 1/R4

Substituting all the values known to us in this formula we get:

1/Rn = 1/4 + 1/8 + 1/12 + 1/24

Making all the denominators into 24 because LCM is 24:

1/Rn = 6 + 3 + 2 + 1 / 24

1/Rn = 12 / 24

1/Rn = 1 / 2

Rn = 2 Ω

Therefore the Lowest resistance which can be obtained by combining these four resistors is 2 Ω.

ii)

Formula that is used to calculate the resistance in series:

Rn = R1 + R2 + R3 + R4.....

Putting the values into this formula we get:

Rn = 4  +  8  +  12  +  24

Rn = 48  Ω

Therefore, the highest resistance which can be obtained by combining these four resistors is 48  Ω.