Question

30 : What is the force required to move a body
of mass 1000 kg if the co-efficient of friction is 0.4
(assume 1kg = 10 N)?​

Answer 1

Answer:

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Step-by-step explanation:

Force due to friction is mgu where m is the mass, g is gravity, and I is the coefficient of friction. That gives you 1000*9.8*0.4 which equals 3920.

If you want the acceleration as well( I know you didn’t ask but I’m bored) you use F=ma. Solve for acceleration gives you a=F/m. 3920/1000=3.92. This means that the maximum acceleration that car can experience is 3.92m/s^2. This applies to speeding up and slowing down.

Answer 2

Answer:

The force required to move a body of mass 1000kg is 4000 N.

Step-by-step explanation:

Given, the mass of a body = 1000 kg

coefficient of friction = 0.4

The force required to move a body is F = μmg, where μ is the coefficient of friction, m is the mass of the body and g is gravity.

F = 1000 * 0.4 *10

  = 4000N

hence, the force required to move 1000 kg if the coefficient of friction is 0.4 will be 4000N.