Question

30°
500 g
50 g
Find the accelerations of blocks A,B & C and tensions in the strings. All the blocks are of equal mass 10
g and F = 300 N
F
Tac
TAB
B
30°
37°
53°
A body of mass 12.5 kg is suspended with the help of
light inextensible strings as shwon in figure. Find tension​

Answer 1

Answer:

1)When the spring is cut the blocks A and B will have a pull equal to k×Δx where Δx is extension in spring between B and C .

From force equilibrium ,before the spring is cut:

kΔx=m C g⇒Δx= kmg

The masses A and B will move with same acceleration as the string is taught between them

a net

= totalmass totalforce

= 2m mg+mg+k× k mg = 3g/2

writing Equation of motion for block B

mg+T=ma net ⇒T=3mg/2−mg=mg/2

acceleration of C will be a C = m kΔx−mg

= m k k mg −mg =0

Don't know dude 〒_〒≥﹏≤

Sorry ≥﹏≤ ≥﹏≤

(╥_╥) (╥﹏╥)

Question bhi thik se likh dete ..kuch samaj hi na a rha kaha se kaha likh diye hoT_T