300
and Z SPR = 30°, find x and y.
Solution : In A TOR, 90° + 40° + x = 180°
T
Therefore,
x = 50°
X х
Now,
Therefore,
400
y = _ SPR + x (Theorem 6.8)
y = 30° +50°
= 80°
S
R
Fig. 6.37
Example 7: In Fig. 6.37, if QT I PR, Z TQR = 40°
(Angle sum property of a triangle)
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