300 apples are distributed equally among A certain number of students had there been had they been 10 more students each would have received one Apple less find the number.
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Answered by
17
let the number of students are x
so each student gets 300/x apples
now if students are x+10
then each one gets 300/x -1 apple
( x+10) (300/x -1 ) = 300
( x+10) (300-x /x ) = 300
( x+10) (300-x ) = 300x
300x - x^2 + 3000 - 10x = 300x
x^2 + 10x - 3000 = 0
x^2 + 60x - 50x -3000 = 0
x (x +60) -50(x+60) = 0
(x +60) (x - 50) = 0
(x +60) = 0 or (x - 50) = 0
x = - 60 or x = 50
but, x = - 60 is not possible
so, x = 50
so each student gets 300/x apples
now if students are x+10
then each one gets 300/x -1 apple
( x+10) (300/x -1 ) = 300
( x+10) (300-x /x ) = 300
( x+10) (300-x ) = 300x
300x - x^2 + 3000 - 10x = 300x
x^2 + 10x - 3000 = 0
x^2 + 60x - 50x -3000 = 0
x (x +60) -50(x+60) = 0
(x +60) (x - 50) = 0
(x +60) = 0 or (x - 50) = 0
x = - 60 or x = 50
but, x = - 60 is not possible
so, x = 50
pravinsir:
mark it as brainliest plz
Answered by
3
Answer:
Step-by-step explanation:
let the number of students are x
so each student gets 300/x apples
now if students are x+10
then each one gets 300/x -1 apple
( x+10) (300/x -1 ) = 300
( x+10) (300-x /x ) = 300
( x+10) (300-x ) = 300x
300x - x^2 + 3000 - 10x = 300x
x^2 + 10x - 3000 = 0
x^2 + 60x - 50x -3000 = 0
x (x +60) -50(x+60) = 0
(x +60) (x - 50) = 0
(x +60) = 0 or (x - 50) = 0
x = - 60 or x = 50
but, x = - 60 is not possible
so, x = 50
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