Chemistry, asked by Mahamadanish, 7 months ago

300 cm3
of an aqueous solution of a protein 2.12 g of the protein, the osmotic pressure
of such a solution at 300 K is found to be 3.89 x 10
-3
bar. Calculate the molar mass of the
protein. (R = 0.0823 L bar mol
-1
K
-1
)

Answers

Answered by shalinee063
2

Answer:

300 cm3

of an aqueous solution of a protein 2.12 g of the protein, the osmotic pressure

of such a solution at 300 K is found to be 3.89 x 10

-3

bar. Calculate the molar mass of the

protein. (R = 0.0823 L bar mol

-1

K

-1300 cm3

of an aqueous solution of a protein 2.12 g of the protein, the osmotic pressure

of such a solution at 300 K is found to be 3.89 x 10

-3

bar. Calculate the molar mass of the

protein. (R = 0.0823 L bar mol

-1

K

-1300 cm3

of an aqueous solution of a protein 2.12 g of the protein, the osmotic pressure

of such a solution at 300 K is found to be 3.89 x 10

-3

bar. Calculate the molar mass of the

protein. (R = 0.0823 L bar mol

-1

K

-1

)

)

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