Question

300 g of water at 25° C is added to 100 g of ice at 0°
C. The final temperature of the mixture in
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Answer 1

Answer:

the final temperature of the mixture is 0°c

Explanation:

latent heat of fusion of ice is 79.7 Cal pergram

let the final temperature be T

m1sdelt=m2L

300×1×(25-T)=100×75

25-T=(100×75)÷300

25-T=25

T=0°C

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