300 gram of Urea M.M =60 gram of water give the solution density 1.7 gram/CC the molarity of solution is
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Answer:
Molarity is defined as the number of moles of solute dissolved in per litre of solution.
Molarity, M=
V
n
n=number of moles of solute=mass/molar mass
V=volume of solution
mass of urea (NH
2
CONH
2
)=120g
Molar mass of urea= 60g/mol
Mass of water=1000g
Density of solution. ρ=1.15 g/mL
n=120/60=2mol
m
solution
=m
solute
+m
solvent
(∵ Law of conservation of mass)
ρ
solution
×V
solution
=120+1000 (using m=ρ.V)
1.15×V
solution
=1120
V
solution
=974mL=0.974L
thus M=
V
n
=
0.974
2
=2.05M
Molarity of the solution is 2.05M
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