Math, asked by arnabghosal22445, 8 months ago

300 grams of salt solution has 40% salt in it how much salt should be added to make it 50% in the solution​

Answers

Answered by akmalkhalid2003
7

Answer:

60 grams.

Step-by-step explanation:

40% is salt in 300 g of salt solution.

Then, quantity of salt = 

 \frac{40 \times 300}{100}  = 120 \: g \\

Now, by the condition in the question,

 \frac{120 + x}{300 + x}  =  \frac{50}{100}  \\ \frac{120 + x}{300 + x}  =  \frac{1}{2}  \\  240 + 2x = 300 + x  \\ Therefore, x = 60 g \\

Please mark as brainliest

Answered by abhinavsingh99626
0

Answer:

40% is salt in 300 g of salt solution.

Then, quantity of salt =

\begin{lgathered}\frac{40 \times 300}{100} = 120 \: g \\\end{lgathered}

100

40×300

=120g

Now, by the condition in the question,

\begin{lgathered}\frac{120 + x}{300 + x} = \frac{50}{100} \\ \frac{120 + x}{300 + x} = \frac{1}{2} \\ 240 + 2x = 300 + x \\ Therefore, x = 60 g \\\end{lgathered}

300+x

120+x

=

100

50

300+x

120+x

=

2

1

240+2x=300+x

Therefore,x=60g

Similar questions