Question

300 J of work is done in sliding a 2 kg block up an inclined plane of height 10m. Taking g=10m/s2, work done against friction is

Answer 1

a)

Work done against gravity = mg sin q × d

= 2 × 10 × 10 (d sinq = 10)

= 200 J

Actual work done = 300 J

Work done against friction = 300 - 200 = 100 J