Physics, asked by himanshi63041, 1 year ago

300 kg of water are lifted 10 m vertically in 5 s.show that the work done is 30 KJ and that the power is 6 KW.

Answers

Answered by satyamsingh51417
11

Answer:

Work done= m ×g× h

so W= 300×10×10= 30000 J or 30 KJ

And Power= Work done/time taken

so P=30000/5=6000W Or 6KW

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