300 kg of water are lifted 10 m vertically in 5 s.show that the work done is 30 KJ and that the power is 6 KW.
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Answer:
Work done= m ×g× h
so W= 300×10×10= 30000 J or 30 KJ
And Power= Work done/time taken
so P=30000/5=6000W Or 6KW
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