Question

300 m road in 2 minutes 30 seconds and then turns around
and jogs 100 m back to point C in another 1 minute. What are
2. Joseph jogs from one end A to the other end B of a straight
Joseph's average speeds
and velocities in jogging (a) from A to
B and (b) from A to c?​

Answer 1

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From point A to B

Distance covered = 300m

Time taken = 2 min 30 sec = (2×60)+30 = 150 sec

Average speed =

$\frac{distence \: covered}{time \: taken} = \frac{300}{150} = 2m \: per \: sec$

Average velocity =

$\frac{displacement}{time \: taken} = \frac{300}{150} = 2m \: per \: sec$

From point A to C

Distance covered = 300 + 100 = 400

Displacement = 300 - 100 = 200

Time taken = 3min 30sec = (3×60)+30 = 210sec

Average speed =

$\frac{distance \: covered}{time \: taken} = \frac{400}{210} = 1.90m \: per \: sec$

Average velocity =

$\frac{displacement}{time \: taken} \: = \frac{200}{210} = 0.95m \: per \: sec$