Question

300J of work is done in sliding a 2kg block up and inclined plane of hight 10m. Work done against friction is ??

Answer 1

(a)
Work done against gravity = mg sin q × d
= 2 × 10 × 10 (d sinq = 10)
= 200 J
Actual work done = 300 J
Work done against friction = 300 - 200 = 100 J

Answer 2

Answer:

Explanation:Work done against gravity = mg sin q × d

= 2 × 10 × 10 (d sinq = 10)

= 200 J

Actual work done = 300 J

Work done against friction = 300 - 200 = 100 J