Question

300j of work is to be done in lifting a bag of mass 5 kg in weight up to height of 4 m from the ground what will be acc with which the bag was revised​

Answer 1

W = F*s

300 = m*a*s

300 = 5*a*4

300/20 = a

15m/s² = a

Answer 2

Please mark as brainliest........

Answer: 15m/s^2

Explanation:

W = F×s

300 = m×a×s

300 = 5×a×4

300=20×a

300/20 = a

15m/s^2 = a