Question

300ml of 1/100molar Ba(oh)2+500ml of 1/100molar Naoh​

Answer 1

Answer:

2HCl + Ba(OH)2 ————-> BaCl2 + 2H2O

Number of moles of HCl added= 0.02 x 10–3 molcm-3 x 100cm3 = 2 x 10–3 mol

Number of moles of Ba(OH)2 added= 0.01 x 10–3 molcm-3 x 200cm3 = 2 x 10–3 mol

Considering limiting reagents,

Number of moles of Ba(OH)2 needed for complete neutralization of HCl = 1 x 10–3 mol of Ba(OH)2

Number of moles of HCl needed for complete neutralization of Ba(OH)2 = 4 x 10–3 mol of HCl

Thus HCl is the limiting factor. So all the HCl get used up after the neutralization reaction. Ba(OH)2 however is in excess so the medium has to be basic.

Ba(OH)2 ————-> Ba2+ + 2OH-

Number of moles of ...