30cm^3 of a gas at2.02 atm and 35 degree celsiys was compressed to 15^cm3 at 35 degree celsius. calculate the final pressure of the gas
Answers
Answered by
21
P1=2.02 atm
V1=30cm^3
T1=25°C
= 25+273=298K
P2=?
V2=15cm^3
T2=35°C=35+273=308K
p1×v1/T1=p2×v2/t2
p2=p1×v1×T1/v2×T1
=2.02×30×308/15×298
= 18664.8/4470=4.17 atm
V1=30cm^3
T1=25°C
= 25+273=298K
P2=?
V2=15cm^3
T2=35°C=35+273=308K
p1×v1/T1=p2×v2/t2
p2=p1×v1×T1/v2×T1
=2.02×30×308/15×298
= 18664.8/4470=4.17 atm
Answered by
10
Hey mate......
here's Ur answer.....
P1 = 2.02 ATM
V1 = 30m^3
T1 = 25 degree Celsius
25 + 273 = 298 K
P2 .....
V2 = 15 m^2
T2 = 35 degree Celsius..
35 + 273 = 308 K
Using formula 2.02 × 30 +× 308/ 15 × 298
= 18664.8/ 4470
4.17 ATM
Hope it Helps❤
here's Ur answer.....
P1 = 2.02 ATM
V1 = 30m^3
T1 = 25 degree Celsius
25 + 273 = 298 K
P2 .....
V2 = 15 m^2
T2 = 35 degree Celsius..
35 + 273 = 308 K
Using formula 2.02 × 30 +× 308/ 15 × 298
= 18664.8/ 4470
4.17 ATM
Hope it Helps❤
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