Question

30g acetic acid is dissolved in 540g of water calculate mole fraction of both the component​

Answer 1

both are similar question

Answer:

Given conditions ⇒

Mass of the Methanol = 60 g.

Molar mass of the Methanol = 32 g/mole.

∵ No. of moles of Methanol =

Molar Mass

Mass

​

∴ No. of moles = 60/32

= 1.875 mole.

Mass of the Water = 120 g.

Molar mass of the water = 18 g/mole.

∴ No. of moles of Water =

Molar mass

Mass

​

.

= 120/18

= 6.67 mole.

Now, Total number of moles in a solution = No. of moles of Methanol + No. of moles of water.

= 1.875 + 6.67

= 8.545 moles.

Now,

Mole Fraction of Methanol in the solution =

Total number of moles in a solutions

No. of moles of Methanol

​

.

= 1.875/8.545

= 0.22

Mole Fraction of Water in the solution =

Total number of moles in a solution

No. of moles of water

​

.

= 6.67/8.545

= 0.78