Question

30g of Co(No3) 2.6H20 in 4.3L of solution.

Answer 1

Mass of CO[NO3]2.6H2O = 30gm


Volume of solution = 4.3L


Molar mass of CO[NO3]2.6H2O = 291 g/mol


no. of moles of solute = 30/291 mol


Molarity of solution = no. of moles of CO[NO3]2.6H2O/ Volume of sol. in litres


                                     = 30/(291*4.3)


                                     = 0.0239 molar

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Answer 2

hello....
weight of solute=30g
volume of solution=4.3L=4300ml
gram molecular mass of solute=291g/mol
molarity=wt. of solute ×1000/gram molecular weight of solute×volume of solution in ml
= 30×1000/291×4300
=30000/1251300
=0.02397mol/lit
hope it helps u...
plss make my answer as brainlest answer......