Question

30g of water at 60^*C is mixed with 20g of water at 10^*C find the resulting temperature of water​

Answer 1

Answer:

40°C.

Explanation:

m1=30g m2=20g

t1= 60°C. t2=10°C

water has a particular specific heat capacity,c=4200J /kg K.

Let the final temperature be t.

m1 c (t1 - t) = m2 c (t - t2)

>30 * (60 - t)= 20 (t - 10). [c gets cancelled]

>1800 - 30t= 20t - 200

>1800 + 200= 20t + 30t

>2000= 50t

>t=2000/50

>t=40

so t is 40°C.