30th term of the AP 10,7,4
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nth term of an AP is given by
tn =a+(n−1)d
In the given sequence, 'a' = 10, 'd' = -3, 'n' = 30.
So, 30th term = t 30 = 10+(30−1)(−3)
⟹t 30=10−87
so,30th term is -77
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