Question

30th term of the AP 10,7,4.......... is

Answer 1

ANSWER

nth term of an AP is given by

t

n

=a+(n−1)d

In the given sequence, 'a' = 10, 'd' = -3, 'n' = 30.

So, 30th term =

t

30

=10+(30−1)(−3)

⟹t

30

=10−87=−77.

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Answer 2

Answer:

-77

Step-by-step explanation:

GIVEN:-

a1 = 10 --------(1)

a2 = 7

a3 = 4

TO FIND:-

a30

SOLUTION:-

d = a2 - a1

d = 7 - 10

d = -3 -------(2)

We know that ,

an = a+(n-1)d

an = a30 and nn= 30

a30 = a + (30-1)d

a30 = a + 29d -------(3)

Put (1) and (2) in (3)

a30 = 10 + 29(-3)

a30 = 10 - 87

a30 = -77