30th term of the ap 10 ,7,4,.........is
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Answered by
18
Hey frnd
your answer is here
common difference of the AP = 7-10 = -3
nth term of an AP whose first term is a and common difference is d is given by
a(n) = a+(n-1)d
so ,for n = 30
a(30) = 10+(30-1)(-3)
a(30) = 10-87
a(30) = -77
Hope this help you
Thanks
Be Brainly
your answer is here
common difference of the AP = 7-10 = -3
nth term of an AP whose first term is a and common difference is d is given by
a(n) = a+(n-1)d
so ,for n = 30
a(30) = 10+(30-1)(-3)
a(30) = 10-87
a(30) = -77
Hope this help you
Thanks
Be Brainly
rimpi79:
thank you
Answered by
8
here first term (a)=10 and common diff (d)= -3 so 30th term a(30)= a+(n-1)d
a(30)=10+(30-1)(-3)
= 10+29(-3)
= 10-87
= -77 answer
a(30)=10+(30-1)(-3)
= 10+29(-3)
= 10-87
= -77 answer
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