Question

30x²-13x-1 find the zero of polynomial

Answer 1

Answer:

$30x {}^{2} - 13x - 1 = 0 \\ 30x {}^{2} - (15x - 2x) - 1 = 0 \\ 30x {}^{2} - 15x + 2x - 1 = 0 \\ 15x(2x - 1) + 1(2x - 1) = 0 \\ (2x - 1)(15x + 1) = 0 \\ x = \frac{1}{2} and \: \: \frac{ - 1}{15}$

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Answer 2

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$30x^2-13x-1=0\\30x^2-15x+2x-1=0\\15x(2x-1)+1(2x-1)=0\\(15x+1)(2x-1)=0\\zeroes\:of\:the\: polynomial\:are$

$\Large\boxed{x=(\frac{1}{2})and(\frac{(-1)}{15}})$.

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