Question

31/10*3/10+7/5-20 is equal to

Answer 1

hope it helps you............

Answer 2

Answer: The final answer is $\dfrac{-1767}{100}$

Step-by-step explanation:

Since we have given that

$\dfrac{31}{10}\times \dfrac{3}{10}+\dfrac{7}{5}-20$

We will use "BODMAS":

So, we first use the multiplication operation:

$\dfrac{31}{10}\times \dfrac{3}{10}+\dfrac{7}{5}-20\\\\=\dfrac{93}{100}+\dfrac{7}{5}-20$

Now, we will add the components :

$\dfrac{93}{100}+\dfrac{7}{5}-20\\\\=\dfrac{93+7\times 20}{100}-20\\\\=\dfrac{93+140}{100}-20\\\\=\dfrac{233}{100}-20$

Now, we will use "Subtraction":

$\dfrac{233}{100}-20\\\\=\dfrac{233-2000}{100}\\\\=\dfrac{-1767}{100}$

Hence, the final answer is $\dfrac{-1767}{100}$